alias cc="CLAUDE_CODE_NO_FLICKER=1 claude --dangerously-skip-permissions --teammate-mode auto"alias ccl="CLAUDE_CODE_NO_FLICKER=1 CLAUDE_CODE_USE_VERTEX=1 CLOUD_ML_REGION=global ANTHROPIC_VERTEX_PROJECT_ID=tech-innovation-prod ANTHROPIC_MODEL=claude-opus-4-6[1m] ANTHROPIC_DEFAULT_OPUS_MODEL=claude-opus-4-6[1m] claude --dangerously-skip-permissions --teammate-mode auto"

It's surprisingly easy

Why? Multi-tenant environments. First, we need to understand a few differences between environments:

• End-user UI
• Agent Runtime Environment
• LLM Server

So

• When you run Claude Code on your local MacBook, the first two are always local. The third is usually the Claude.ai server.
• When you ssh to a virtual private server (VPS) and install Claude Code there, the first two are your remote server. The third is still the Claude.ai server.
• When you run Claude RC on your virtual private server and code from your iPad using the Claude app, the end-user UI is on your iPad, the agent runtime environment is on your VPS, and the server is still Claude.ai.

Most people physically separate their tenancy, such as Claude Code, from their personal vs. work laptops. So in most cases, it's not a big deal.

But when you need multi-tenancy, it becomes super stressful. For example, say you have two different toolkits:

• personal toolkits (personal Notion, personal Sentry, personal Linear)
• workplace toolkits (company Notion, company Sentry, company Linear)

Most MCP auth states or code harnesses don't support profiles, so you can only log in to one.

So therefore... a natural evolution was to have both:

• a personal VPS with all personal toolkits set up
• a workplace VPS with all workspace toolkits set up

to physically isolate tenancies.

Now we've solved the multiple-profile issue, but the client's problems persist. Now let's get back to the environments:

• End-user UI
• Agent Runtime Environment
• LLM Server

All MCP auth or toolkit auth info should always be saved in the Agent Runtime Environment IMHO. However, a surprising number of harnesses tie them to the LLM server (such as Codex Apps or Claude.ai Plugins) or put them in the end-user UI (Claude Desktop or Codex Desktop).

Now the problem is:

• If the auth data is put on the LLM server, you cannot reuse LLM accounts across tenants
• If the auth data is put on the end-user UI, you cannot use the same app to access multi-tenants.

The only way to reliably isolate different auth information is thus:

• You ssh to a virtual private server (VPS) and run Claude Code there. Never use LLM server plugins.

Then

• End-user UI
• Agent Runtime Environment

are both isolated VPS, and

• LLM Server holds no information on the tenancy

This way, you can provide different toolkits, creating multiple dev environments.

Dynamic Programming

• Optimal substructure. The optimal solution to a problem consists of optimal solutions to subproblems.
• Overlapping subproblems. few subproblems in total, many recurring instances of each.

Bellman-Ford

shortest path, negative possible.

Chain Matrix Multiplication

Min Cut

The set of vertices reachable from source s in the residual graph is one part of the partition. Cut capacity $\text{cap}(A, B) = \sum_{\text{out A}} c(e)$.

• maxflow = Min $\text{cap}(A, B)$.

Ford-Fulkerson

Given $(G, s, t, c \in \mathbb{N}+)$, start with $f(u,v)=0$ and $G_f =G$. While an augmenting path is in $G_f$, find a bottleneck. Augment the flow along this path and update the residual graph $G_f$. $\mathcal{O}(|f| (V+E))$.

Edmond-Karp

Ford-Fulkerson, but choose the shortest augmenting path.

For any flow $f$ and any $(A,B)$ cut, $|f| ≤ \text{cap}(A,B)$. For any flow $f$ and any $(A,B)$ cut, $|f| = \sum_f (s, v) = \sum_{u \in A,~v \in B} f(u, v) - \sum_{u \in A,~v \in B} f(v, u)$

Solving by Reduction

To reduce a problem $Y$ to a problem $X$ ($Y \leq_{p} X$) we want a function $f$ that maps $Y$ to $X$ such that $f$ is a polynomial time computable and $\forall y \in Y$ is solvable if and only if $f(y) \in X$ is solvable.

Reduction to NF

Describe how to construct a flow network. Claim "This is feasible if and only if the max flow is …". Prove both directions.

Bipartite to Max Flow

• Max Matching ⟹ Max Flow. If k edges are matched, then there is a flow of value k.
• Max matching ⟸ Max flow. If there is a flow f of value k, there is a matching with k edges.
• $\mathcal{O}(|f| (E' + V'))$
• $|f| = V$
• $V' = 2V + 2$
• $E' = E + 2V$
• $\mathcal{O}(V (E + 2V + 2V + 2)) = \mathcal{O}(V E + V^2) = \mathcal{O}(V E)$

Circulation

• $d(v) > 0$ if demand
• $d(v) < 0$ if supply
• Capacity Constraint $0 \leq f(e) \leq c(e)$
• Conservation Constraint $f^{\text{in}} (v) - f^{\text{out}} (v) = d(v)$.
• For every feasible circulation $\sum_{v \in V} d(v) = 0$, there is a feasible circulation with demands $d(v)$ in $G$ if and only if the maximum $s-t$ flow in $G'$ has value $D = \sum_{d(v)>0} d(v)$.

Circulation with Demands and Lower Bounds.

• Capacity Constraint $l(e) \leq f(e) \leq c(e)$
• Conservation Constraint $f^{\text{in}} (v) - f^{\text{out}} (v) = d(v)$
• Given $G$ with lower bounds, we subtract the lower bound $l(e)$ from the capacity of each edge.
• Subtract $f_0^{\text{in}}(v) − f_0^{\text{out}}(v) = L(v)$ from the demand of each node.
• Solve the circulation problem on this new graph to get a flow $f$.
• Add $l(e)$ to every $f(e)$ to get a flow for the original graph.

Existence of Linear Programming Solution.

• Given an Linear Programming problem with a feasible set and an objective function $P$.
• If $S$ is empty, Linear Programming has no solution.``
• If $S$ is unbounded, Linear Programming may or may not have the solution.
• If $S$ is bounded, Linear Programming has one or more solutions.

Standard Form Linear Programming

• $\max (c_1x_1 + \cdots + c_nx_n)$
• subject to
• $a_{11}x_1 + \cdots + a_{1n}x_n ≤ b_1$
• all the way to
• $a_{m1}x_1 + \cdots + a_{mn}x_n ≤ b_m$.
• Also, $x_1 \geq 0, \cdots, x_n \geq 0$.

Matrix Form Linear Programming

• $\max(c^T x)$
• subject to
• $Ax \leq b$
• $x \geq 0$
• $x \in \mathbb{R}$

Integer Linear Program

• all variables $\in \mathbb{N}$
• is NP-Hard

Dual Program

• $\min(b^T y)$
• subject to
• $A^T y \geq c$
• $y \geq 0$
• $y \in \mathbb{R}$

Weak Duality

• The optimum of the dual is an upper bound to the optimum of the primal.
• $\text{OPT}(\text{primal}) ≤ \text{OPT}(\text{dual})$.

Strong duality

• Let P and D be primal and dual Linear Programming correspondingly. If P and D are feasible, then $c^T x = b^T y$.

If a standard problem and its dual are feasible, both are feasibly bounded. If one problem has an unbounded solution, then the dual of that problem is infeasible.

Possibilities of Feasibility

P vs. NP

• P = set of poly-time solvable problems.
• NP = set of poly-time verifiable problems.
• Decision Knapsack is NP-complete, whereas undecidable problems like Halting problems are only NP-Hard (not NP).
• X is NP-Hard if $\forall Y \in NP$ and $Y \leq_p X$.
• X is NP-complete if X is NP-Hard and $X \in NP$.
• If P = NP, then P = NP-complete.
• NP Problems can be solved in poly-time with NDTM.
• NP Problems can be verified in poly-time by DTM.

Polynomial Reduction

To reduce a decision problem Y to a decision problem X ($Y \leq_p X$), find a function $f$ that maps Y to X such that $f$ is poly-time computable and $\forall y \in Y$ is YES if and only if $f(y) \in X$ is YES.

Proving NP-Complete

Show X is in NP, Pick problem NP-complete Y, and show $Y \leq_p X$.

Conjunctive Normal Form SAT

• Conjunction of clauses.
• Literal: Variable or its negation.
• Clause: Disjunction of literals.
• 3-SAT. Each clause has at most three literals.
• $(X_1 \lor \neg X_3) \land (X_1 \lor X_2 \lor X_4) \land \cdots$

Independent Set

• Independent Set is a set of vertices in a graph, no two of which are adjacent.
• The max independent set asks for the size of the largest independent set in a given graph.

Clique

• Complete graph = every pair of vertices is connected by an edge.
• The max clique asks for the number of vertices in its largest complete subgraph.

Vertex Cover

• Vertex Cover of a graph is a set of vertices that includes at least one endpoint of every edge.
• The min vertex cover asks for the size of the smallest vertex cover in a graph.

Hamiltonian Cycle

• A cycle that visits each vertex exactly once.
• Hamiltonian Path visits each vertex exactly once and doesn't need to return to its starting point.

Graph Coloring

• Given G, can you color the nodes with $<k$ colors such that the end points of every edge are colored differently?