Poisson Approximation
$P (\lambda) = {{e^{-\lambda} \lambda^x} \over x!}$
$b \rightarrow^d p$ if $n >> 1$, $p << 1$ and $\lambda = np$
In Probability,
(xnโ)=x!(nโx)!n!โ b(n,p)=Poisson(ฮป)ย whereย ฮป=np nโซ1ย andย pโช1approximates binomial distribution.
bโpโบnโซ1ย &ย pโช1ย &ย ฮป=npwhere $b$ is binomial and $p$ is poisson