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Probability Of Queueing (Internetworking) · cho.sh

Probability Of Queueing (Internetworking)

Probability Of Queueing (Internetworking)

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This post is more than a year old. Information may be outdated.

Suppose

Total Users: $n$
Each has a probability of $p$ being active

The probability that exactly $k$ users are present is:

\binom{n}{k} \times (1-p) ^ {n-k} \times p^k

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Internetworking

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