De Morgan Law
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${(A \cup B)}^C = A^C \cap B^C$
${(A \cap B)}^C = A^C \cup B^C$
This post is more than a year old. Information may be outdated.
${(A \cup B)}^C = A^C \cap B^C$
${(A \cap B)}^C = A^C \cup B^C$