Light Version Of Famous Task

The ABC conjecture (also known as the Oesterlé--Masser conjecture) is a famous conjecture in number theory, first proposed by Joseph Oesterlé and David Masser. It is formally stated as follows:

For every positive real number $\varepsilon$, there are only finitely many positive integer triples $(a, b, c)$ such that 

1. $a$ and $b$ are relatively prime;
2. $a + b = c$; and
3. $c > \text{rad}(abc)^{1+\varepsilon}$, 

where $\text{rad}(n) = \prod\_{\substack{p|n \\\ p \in \text{Prime}}} p$ is the product of all distinct prime divisors of $n$. 

Shinichi Mochizuki claimed to have proven this conjecture in August 2012. Later, Mochizuki's claimed proof was announced to be published in Publications of the Research Institute for Mathematical Sciences (RIMS), a journal of which Mochizuki is the chief editor.

Spike is a great fan of number theory and wanted to prove the ABC conjecture as well. However, due to his inability, he turned to work on a weaker version of the ABC conjecture, which is formally stated as follows:

Given a positive integer $c$, determine if there exists positive integers $a,b$, such that $a+b=c$ and $\text{rad}(a b c)\<c$.

Note that in the original ABC conjecture, the positive integers $a$ and $b$ are required to be relatively prime. However, as Spike is solving an easier version of the problem, this requirement is removed.

The first line of input contains one integer $T$ $(1 \leq T \leq 10)$, the number of test cases.

The next lines contain description of the $t$ test cases. Each test case contains one line, including an integer $c$ $(1\leq c \leq 10^{18})$.

For each test case, if there exist two positive integers $a,b$ satisfying $a+b=c$ and $\text{rad}(a b c)\<c$, then output yes in a line, otherwise output no instead.

For the first test case, we have $2+2=4$ and $\text{rad}(2\times 2\times 4)=2<4$.

For the second test case, we have $6+12=18$ and $\text{rad}(6\times 12\times 18)=6<18$.

For the third test case, there's no solution.