MemexBinomial DistributionBinomial DistributionIn Probability,2 outcomes1 or more trials → nnn trialsXXX is the number of heads (successes).x∈{0, 1, 2, ⋯ , n}x \in \{0,~1,~2,~\cdots~,~n\}x∈{0, 1, 2, ⋯ , n}Then,P(X=x)=(nx)pxqn−xP(X = x) = {n \choose x} p^x q^{n-x}P(X=x)=(xn)pxqn−x