Exact a to the power b

You are given a real number $a$ and an integer $b$. Write a program that computes $a^b$ exactly, with no rounding error.

The fractional part of $a$ has finitely many digits, so $a^b$ is also a finite decimal. Double precision floating point does not hold enough digits for it, so compute with integer arithmetic.

The first line contains $a$ and $b$, separated by a space. ($0 < a < 100$, $1 \le b \le 100$)

$a$ always contains a decimal point and has at most 9 digits after it. The last digit after the decimal point is not 0.

Print the exact value of $a^b$ on the first line.

If $a$ has $k$ digits after the decimal point, the answer has exactly $k \times b$ digits after the decimal point. Do not round, do not drop digits, and do not append extra zeros. When the integer part is 0, the line starts with 0..