Spiral

You place beans on an $N \times N$ board, one bean per square, in the spiral order shown in the figure.

Start at the top left square $(1, 1)$ and move right. When the next square is off the board or already holds a bean, turn down. The same rule turns down into left, left into up, and up back into right, so the direction cycles right, down, left, up until all $B$ beans are placed.

Given $N$ and $B$, find the coordinates of the square that holds the last bean. A coordinate $(L, C)$ means row $L$ counted from the top and column $C$ counted from the left. The figure shows $N = 8$ and $B = 53$, where the last bean lands on $(4, 6)$.

One line with two integers $N$ and $B$ separated by a space, where $1 \le N \le 2^{30}$ and $1 \le B \le N^2$.

Print the row number $L$ and the column number $C$ of the last bean on one line, separated by a space.