Buffon's Needle

For millennia, people have been interested in approximating $\pi$. One famous method is Buffon's Needle: draw a vertical line at every integer $x$ coordinate in the plane (so there are lines $x = 0$, $x = 1$, $x = -1$, and so on) and drop a bunch of needles of length $1$ on it. Each needle either intersects a vertical line or lies entirely between two vertical lines. It turns out that if the needles are dropped randomly, the fraction of needles that intersect a vertical line can be used to approximate $\pi$. (The specific assumptions about exactly how the needles are dropped in the experiment are not important for this problem.)

In particular, let $x$ be the fraction of needles that intersect a vertical line. Then

$\pi \approx \frac{2}{x}.$

You are given the positions of $N$ needles (not necessarily random), and at least one of them intersects a vertical line. Using the formula above, find the corresponding approximation of $\pi$.

The first line of input contains a single integer $N$ ($1 \leq N \leq 10^4$), the number of needles. $N$ lines follow.

The $i$-th such line describes the $i$-th needle. It contains four real numbers: $x_{i1}, y_{i1}, x_{i2}, y_{i2}$. This means that the $i$-th needle has one endpoint at $(x_{i1}, y_{i1})$ in the plane and the other endpoint at $(x_{i2}, y_{i2})$.

All real numbers in the input are given with exactly $6$ digits after the decimal point and have absolute value at most $10$. Furthermore, no $x$ coordinate in the input is within $10^{-6}$ of an integer.

Since all the needles are of length $1$, for each $i$ it is guaranteed that

$|(x_{i1} - x_{i2})^2 + (y_{i1} - y_{i2})^2 - 1| < 10^{-3}.$

Output a single real number, the approximation of $\pi$ described above. Your answer is considered correct if its absolute or relative error is at most $10^{-6}$.

In the first sample, the first needle intersects a vertical line ($x = 1$), but the second does not. So the fraction of needles that intersect vertical lines is $1/2$ and the corresponding approximation of $\pi$ is $4$.

In the second sample, both needles intersect vertical lines ($x = 1$ and $x = 0$), so the fraction of needles that intersect vertical lines is $1$ and the corresponding approximation of $\pi$ is $2$.