Algorithm Class - Insertion Sort 3
InterviewTime limit1sMemory limit512 MB
Simulate insertion sort on array A and print 1 if the array ever equals B during the process, otherwise 0.
- Level
Medium5 of 10
- Topics
- Simulation, Implementation, Sorting, Array
- Solved
- No attempts yet
Problem
Seojun is again working as a teaching assistant for the insertion sort class. Let us check through a problem whether the students understood what his father taught in class.
There is an array A holding N distinct positive integers. When array A is sorted in ascending order with insertion sort, check whether array A ever equals array B during the sorting process. The initial state of array A also counts as a state that can occur during sorting.
The pseudocode for insertion sort on an array of size N is as follows.
insertion_sort(A[1..N]) { # sorts A[1..N] in ascending order
for i <- 2 to N {
loc = i - 1;
newItem = A[i];
# at this point A[1..i-1] is already sorted
while (1 <= loc and newItem < A[loc]) {
A[loc + 1] <- A[loc];
loc--;
}
if (loc + 1 != i) then A[loc + 1] = newItem;
}
}
Input
The first line gives the size N of arrays A and B (5 ≤ N ≤ 10,000).
The next line gives the elements of array A, A1, A2, ..., AN, which are distinct. (1 ≤ Ai ≤ 109)
The next line gives the elements of array B, B1, B2, ..., BN. (1 ≤ Bi ≤ 109)
Output
Print 1 if array A equals array B at some point while insertion sort sorts array A in ascending order, and 0 otherwise.