Algorithm Class - Depth-First Search 4
InterviewTime limit1sMemory limit512 MB
Run an iterative DFS from vertex R on an undirected graph, visiting neighbors in descending order, and print each vertex's depth in the DFS tree or -1 if unvisited.
- Level
Medium4 of 10
- Topics
- DFS, Graph, Stack, Implementation
- Solved
- No attempts yet
Problem
Seojun is assisting the depth-first search (DFS) class again today. Let us check through a problem whether the students understood what his father taught in class.
An undirected graph with N vertices and M edges is given. The vertices are numbered 1 through N, and every edge has weight 1. The tree produced by a depth-first search starting at vertex R is called a depth-first search tree. Print the depth of every node in the depth-first search tree. The starting vertex R has depth 0, and an unvisited node is printed with depth -1.
The pseudocode for the depth-first search is as follows. Adjacent vertices are visited in descending order.
dfs(V, E, R) { # V : vertex set, E : edge set, R : starting vertex
visited[R] <- YES; # mark the starting vertex R as visited.
for each x ∈ E(R) # E(R) : set of vertices adjacent to vertex R. (visit vertices in descending order of vertex number)
if (visited[x] = NO) then dfs(V, E, x);
}
Input
The first line gives the number of vertices N (5 ≤ N ≤ 100,000), the number of edges M (1 ≤ M ≤ 200,000), and the starting vertex R (1 ≤ R ≤ N).
The next M lines give edge information u v, representing a bidirectional edge of weight 1 between vertex u and vertex v. (1 ≤ u < v ≤ N, u ≠ v) Every pair (u, v) of an edge is distinct.
Output
Print one integer on each of N lines, starting from the first line. The i-th line gives the depth of vertex i. The starting vertex R has depth 0, and an unvisited node is printed with depth -1.