Sum of Cubes

Class taught Eunha the following formula relating the sum of the integers from $1$ to $N$ and the sum of their cubes.

• $(1 + 2 + \cdots + N)^2 = 1^3 + 2^3 + \cdots + N^3$

Eunha found this hard to believe, so she decided to check it by writing code. Print the sum of the integers from $1$ to $N$, then the square of that sum, then the sum of the cubes of the integers from $1$ to $N$, in that order.

The first line contains an integer $N$. $(5 \le N \le 100)$

Print three lines.

• Line 1: the sum $1+2+\cdots+N$.
• Line 2: the square of that sum, $(1+2+\cdots+N)^2$.
• Line 3: the sum of cubes $1^3+2^3+\cdots+N^3$.

The square of $a$ is $a$ multiplied by itself twice, written $a^2$. $a^2 = a \times a$.

The cube of $a$ is $a$ multiplied by itself three times, written $a^3$. $a^3 = a \times a \times a$.