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Probability

Drafting

Unconditional - Total Prob Conditional - Bayes' Theorem

P(E)=P(EH)P(H)+P(EHC)P(HC)P(E) = P(E|H)P(H) + P(E|H^C) P(H^C)

Discrete Distributions

f(x)=P(X=x)f(x) = P(X=x)

Uniform Distributions (Discrete)

Ω={a1,  an}\Omega = \{a_1, ~ \cdots ~ a_n\}
P(X=x)=1n=1ΩP(X=x) = {1 \over n} = {1 \over {|\Omega|}}