Geometric Series

In Probability,

$$\sum\limits_{j=k}^{N} a^j = {{a^k - a^{N+1} \over {1-a}}}$$ $$~\text{if}~ |a| < 1, ~\sum\limits_{j=k}^{\infty} a^j = \lim_{N \to \infty} \sum\limits_{j=k}^{N} a^j = {{a^k \over {1-a}}}$$ $$\sum\limits_{j=1}^{\infty} a^j = {a \over {1-a}}$$ $$\sum\limits_{j=0}^{\infty} a^j = {a \over {1-a}}$$ $$\sum\limits_{j=1}^{\infty} ja^j= {a \over {(1-a)^2}}$$ $$\sum\limits_{j=0}^{\infty} ja^j= {a \over {(1-a)^2}}$$ $$\sum\limits_{j=1}^{\infty} j^2 a^j= {{a + a^2} \over {(1-a)^2}}$$ $$\sum\limits_{j=0}^{\infty} j^2 a^j= {{a + a^2} \over {(1-a)^2}}$$