Binomial DistributionIn Probability, 2 outcomes 1 or more trials → nnn trials XXX is the number of heads (successes). x∈{0, 1, 2, ⋯ , n}x \in \{0,~1,~2,~\cdots~,~n\}x∈{0, 1, 2, ⋯ , n} Then, P(X=x)=(nx)pxqn−xP(X = x) = {n \choose x} p^x q^{n-x}P(X=x)=(xn)pxqn−x