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Multiplication Theorem

In Probability,

P(A∩B)=P(A)P(B∣A){P(A \cap B)} = P(A)P(B|A)
P(A∩B∩C)=P(A)P(B∣A)P(C∣A∪B){P(A \cap B \cap C)} = P(A)P(B|A)P(C|A \cup B)

If AA, BB, and CC are all independent, it would be a simple multiplication of P(A)P(B)P(C)P(A)P(B)P(C) and so on.