MemexMultiplication TheoremMultiplication TheoremIn Probability,P(A∩B)=P(A)P(B∣A){P(A \cap B)} = P(A)P(B|A)P(A∩B)=P(A)P(B∣A)P(A∩B∩C)=P(A)P(B∣A)P(C∣A∪B){P(A \cap B \cap C)} = P(A)P(B|A)P(C|A \cup B)P(A∩B∩C)=P(A)P(B∣A)P(C∣A∪B)If AAA, BBB, and CCC are all independent, it would be a simple multiplication of P(A)P(B)P(C)P(A)P(B)P(C)P(A)P(B)P(C) and so on.