Multiplication Theorem

In Probability,

$${P(A \cap B)} = P(A)P(B|A)$$

$${P(A \cap B \cap C)} = P(A)P(B|A)P(C|A \cup B)$$

If $A$, $B$, and $C$ are all independent, it would be a simple multiplication of $P(A)P(B)P(C)$ and so on.