S(n,m) = SUM (j = i to n) (jm)S(n,m) = SUM (k = 1 to m+1) (F(m,k) * nk)S(n,1) = (1 + ... + n) = (1/2)*n2 + (1/2)*nS(n,2) = (1 + ... + n2) = (1/3)*n3 + (1/2)*n2 + (1/6)*nS(n,3) = (1 + ... + n3) = (1/4)*n4 + (1/2)*n3 + (1/4)*n2S(n,4) = (1 + ... + n4) = (1/5)*n5 + (1/2)*n4 + (1/3)*n3 - (1/30)*n