배열에서 점 갱신이 일어나고, 각 구간 질의마다 엄격한 다수 원소가 i인 부분배열의 개수에 i를 곱한 합을 998244353으로 나눈 나머지를 구한다.
어려움9세그먼트 트리분할 정복조합론구현아직 제출이 없습니다시간 제한2초메모리 제한512 MBMajorant of a multiset is an element which occurs more frequently than all other elements combined. Some multisets do not have majorant.
Given is an array containing n positive integers a[1], a[2], ..., a[n]. A subarray of array a is the sequence a[l], a[l+1] … a[r], where 1 ≤ l ≤ r ≤ n.
We consider m queries of two types:
First line of the standard input contains the number n. The second line of the standard input contains n integers – the element of the given array. The third line of the standard input contains the number m. From each of the next m lines read 3 numbers: l, r and t - the query in an encrypted form.
To decrypt the query: Let last_output be the last number on the standard output produced by your program (or 0, if there are no such)
Compute type=((t+last_output) mod 2) +1
If type=1 the query is "Update" with p=((l+last_output) mod n)+1, q=((r+last_output) mod 100 000 000)+1
If type=2, the query is "Query" with p=((l+last_output) mod n)+1, q=((r+last_output) mod n)+1
For every query of type 2, output on a separate line the answer to the query.
After decrypting, the first query becomes “query, p=1, q=4”. There are 2 subarrays with majorant 1 and 5 with majorant 2 so the answer is 2*1+5*2=12.
The second query becomes “update, p=3, q=3”. After that, the array becomes: 1, 2, 3, 1.
The third query is: “query, p=1, q=3”. There is 1 subarray with majorant 1, 1 with majorant 2 and 1 with majorant 3.