Room Number

Taekhee moved into room $N$ of the Yonsei Building in Yonsei-dong. He wants to put the room number on his door with digit stickers, but the sticker set holds exactly one sticker for each digit from 0 to 9. If the same digit appears twice in the room number, he cannot spell it out.

Instead of spelling $N$ itself, Taekhee decided to put up two natural numbers $A$ and $B$ with $A + B = N$. Every digit used in $A$ and $B$ must be different, so each digit from 0 to 9 can appear at most once across the two numbers. The stickers have an unusual shape, so a 6 cannot be turned upside down and used as a 9. Both $A$ and $B$ are natural numbers written without leading zeros.

Take the room number 555. The split 123 + 432 fails because 2 and 3 are each used twice, and 99 + 456 fails because 9 is used twice. The split 512 + 43 uses no digit twice, so it works. A room number usually admits several such splits.

The room number is fairly large, so Taekhee cannot find $A$ and $B$ quickly. Help him.

The first line contains the room number $N$. ($1 \le N \le 10^9$)

If no $A$ and $B$ satisfy the condition, print -1 on the first line.

Otherwise, among all pairs that satisfy the condition, take the one with the smallest $A$ and print it in the form A + B, that is, $A$, a space, a plus sign, a space, then $B$. Since $B = N - A$, exactly one answer follows this rule.