Discrete Mathematics
Dynamic Programming
- Optimal substructure. The optimal solution to a problem consists of optimal solutions to subproblems.
- Overlapping subproblems. few subproblems in total, many recurring instances of each.
Bellman-Ford
shortest path, negative possible.
OPT[v,k]=min(OPT[v,k−1],OPT[u,v]+w(u,v))Chain Matrix Multiplication
OPT[i,j]=OPT[i,k]+OPT[k+1,j]+combineMin Cut
The set of vertices reachable from source s in the residual graph is one part of the partition. Cut capacity $\text{cap}(A, B) = \sum_{\text{out A}} c(e)$.
∣f∣=e out of X∑f(e)−e into X∑f(e)- maxflow = Min $\text{cap}(A, B)$.
Ford-Fulkerson
Given $(G, s, t, c \in \mathbb{N}+)$, start with $f(u,v)=0$ and $G_f =G$. While an augmenting path is in $G_f$, find a bottleneck. Augment the flow along this path and update the residual graph $G_f$. $\mathcal{O}(|f| (V+E))$.
Edmond-Karp
Ford-Fulkerson, but choose the shortest augmenting path.
For any flow $f$ and any $(A,B)$ cut, $|f| ≤ \text{cap}(A,B)$. For any flow $f$ and any $(A,B)$ cut, ∣f∣=∑f(s,v)=∑u∈A, v∈Bf(u,v)−∑u∈A, v∈Bf(v,u)
Solving by Reduction
To reduce a problem $Y$ to a problem $X$ ($Y \leq_{p} X$) we want a function $f$ that maps $Y$ to $X$ such that $f$ is a polynomial time computable and $\forall y \in Y$ is solvable if and only if $f(y) \in X$ is solvable.
Reduction to NF
Describe how to construct a flow network. Claim "This is feasible if and only if the max flow is …". Prove both directions.
Bipartite to Max Flow
- Max Matching ⟹ Max Flow. If k edges are matched, then there is a flow of value k.
- Max matching ⟸ Max flow. If there is a flow f of value k, there is a matching with k edges.
- $\mathcal{O}(|f| (E' + V'))$
- $|f| = V$
- $V' = 2V + 2$
- $E' = E + 2V$
- $\mathcal{O}(V (E + 2V + 2V + 2)) = \mathcal{O}(V E + V^2) = \mathcal{O}(V E)$
Circulation
- $d(v) > 0$ if demand
- $d(v) < 0$ if supply
- Capacity Constraint $0 \leq f(e) \leq c(e)$
- Conservation Constraint $f^{\text{in}} (v) - f^{\text{out}} (v) = d(v)$.
- For every feasible circulation $\sum_{v \in V} d(v) = 0$, there is a feasible circulation with demands $d(v)$ in $G$ if and only if the maximum $s-t$ flow in $G'$ has value $D = \sum_{d(v)>0} d(v)$.
Circulation with Demands and Lower Bounds.
- Capacity Constraint $l(e) \leq f(e) \leq c(e)$
- Conservation Constraint $f^{\text{in}} (v) - f^{\text{out}} (v) = d(v)$
- Given $G$ with lower bounds, we subtract the lower bound $l(e)$ from the capacity of each edge.
- Subtract $f_0^{\text{in}}(v) − f_0^{\text{out}}(v) = L(v)$ from the demand of each node.
- Solve the circulation problem on this new graph to get a flow $f$.
- Add $l(e)$ to every $f(e)$ to get a flow for the original graph.
Existence of Linear Programming Solution.
- Given an Linear Programming problem with a feasible set and an objective function $P$.
- If $S$ is empty, Linear Programming has no solution.``
- If $S$ is unbounded, Linear Programming may or may not have the solution.
- If $S$ is bounded, Linear Programming has one or more solutions.
Standard Form Linear Programming
- $\max (c_1x_1 + \cdots + c_nx_n)$
- subject to
- $a_{11}x_1 + \cdots + a_{1n}x_n ≤ b_1$
- all the way to
- $a_{m1}x_1 + \cdots + a_{mn}x_n ≤ b_m$.
- Also, $x_1 \geq 0, \cdots, x_n \geq 0$.
Matrix Form Linear Programming
- $\max(c^T x)$
- subject to
- $Ax \leq b$
- $x \geq 0$
- $x \in \mathbb{R}$
Integer Linear Program
- all variables $\in \mathbb{N}$
- is NP-Hard
Dual Program
- $\min(b^T y)$
- subject to
- $A^T y \geq c$
- $y \geq 0$
- $y \in \mathbb{R}$
Weak Duality
- The optimum of the dual is an upper bound to the optimum of the primal.
- $\text{OPT}(\text{primal}) ≤ \text{OPT}(\text{dual})$.
Strong duality
- Let P and D be primal and dual Linear Programming correspondingly. If P and D are feasible, then $c^T x = b^T y$.
If a standard problem and its dual are feasible, both are feasibly bounded. If one problem has an unbounded solution, then the dual of that problem is infeasible.
Possibilities of Feasibility
| P\D | Feasibly Bounded | Feasibly Unbounded | Infeasible |
|---|---|---|---|
| Feasibly Bounded | Possible | Impossible | Impossible |
| Feasibly Unbounded | Impossible | Impossible | Possible |
| Infeasible | Impossible | Possible | Possible |
P vs. NP
- P = set of poly-time solvable problems.
- NP = set of poly-time verifiable problems.
- Decision Knapsack is NP-complete, whereas undecidable problems like Halting problems are only NP-Hard (not NP).
- X is NP-Hard if $\forall Y \in NP$ and $Y \leq_p X$.
- X is NP-complete if X is NP-Hard and $X \in NP$.
- If P = NP, then P = NP-complete.
- NP Problems can be solved in poly-time with NDTM.
- NP Problems can be verified in poly-time by DTM.
Polynomial Reduction
To reduce a decision problem Y to a decision problem X ($Y \leq_p X$), find a function $f$ that maps Y to X such that $f$ is poly-time computable and $\forall y \in Y$ is YES if and only if $f(y) \in X$ is YES.
Proving NP-Complete
Show X is in NP, Pick problem NP-complete Y, and show $Y \leq_p X$.
Conjunctive Normal Form SAT
- Conjunction of clauses.
- Literal: Variable or its negation.
- Clause: Disjunction of literals.
- 3-SAT. Each clause has at most three literals.
- $(X_1 \lor \neg X_3) \land (X_1 \lor X_2 \lor X_4) \land \cdots$
Independent Set
- Independent Set is a set of vertices in a graph, no two of which are adjacent.
- The max independent set asks for the size of the largest independent set in a given graph.
Clique
- Complete graph = every pair of vertices is connected by an edge.
- The max clique asks for the number of vertices in its largest complete subgraph.
Vertex Cover
- Vertex Cover of a graph is a set of vertices that includes at least one endpoint of every edge.
- The min vertex cover asks for the size of the smallest vertex cover in a graph.
Hamiltonian Cycle
- A cycle that visits each vertex exactly once.
- Hamiltonian Path visits each vertex exactly once and doesn't need to return to its starting point.
Graph Coloring
- Given G, can you color the nodes with $<k$ colors such that the end points of every edge are colored differently?