Approximation
In Probability,
lnn!=lnk=1∏nk=k−1∑nlnk≈∫x=1nlnx dxUsing integration by parts
∫u dv=uv−∫v du d(uv)=v du+u dv u=lnx, dv=1, du=x1, v=x ∫x=1nlnx dx=[xlnx−∫xx1 dx]x=1n =[xlnx−x]x=1n=nlnn−n+1In Probability,
lnn!=lnk=1∏nk=k−1∑nlnk≈∫x=1nlnx dxUsing integration by parts
∫u dv=uv−∫v du d(uv)=v du+u dv u=lnx, dv=1, du=x1, v=x ∫x=1nlnx dx=[xlnx−∫xx1 dx]x=1n =[xlnx−x]x=1n=nlnn−n+1