Poisson Approximation
$P (\lambda) = {{e^{-\lambda} \lambda^x} \over x!}$
$b \rightarrow^d p$ if $n >> 1$, $p << 1$ and $\lambda = np$
In Probability,
(xn)=x!(n−x)!n! b(n,p)=Poisson(λ) where λ=np n≫1 and p≪1approximates binomial distribution.
b→p⟺n≫1 & p≪1 & λ=npwhere $b$ is binomial and $p$ is poisson