Binomial DistributionIn Probability, 2 outcomes 1 or more trials → $n$ trials $X$ is the number of heads (successes). $x \in {0,1,2,\cdots,~n}$ Then, P(X=x)=(nx)pxqn−xP(X = x) = {n \choose x} p^x q^{n-x}P(X=x)=(xn)pxqn−x